(x-3)(x+14)=0

Solution for (x-3)(x+14)=0 equation:

(x-3)(x+14)=0

We multiply parentheses ..

(+x^2+14x-3x-42)=0

We get rid of parentheses

x^2+14x-3x-42=0

We add all the numbers together, and all the variables

x^2+11x-42=0

a = 1; b = 11; c = -42;
Δ = b2-4ac
Δ = 112-4·1·(-42)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-17}{2*1}=\frac{-28}{2}
=-14
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+17}{2*1}=\frac{6}{2}
=3
$