5(x+2)+6(x-1)=48

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Solution for 5(x+2)+6(x-1)=48 equation: 



5(x+2)+6(x-1)=48

We move all terms to the left:

5(x+2)+6(x-1)-(48)=0

We multiply parentheses

5x+6x+10-6-48=0

We add all the numbers together, and all the variables

11x-44=0

We move all terms containing x to the left, all other terms to the right

11x=44

x=44/11

x=4

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