z=12+(3/5)z

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Solution for z=12+(3/5)z equation: 



z=12+(3/5)z

We move all terms to the left:

z-(12+(3/5)z)=0



Domain of the equation: 5)z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

z-(12+(+3/5)z)=0

We multiply all the terms by the denominator


z*5)z)-(12+(+3=0

Wy multiply elements

5z^2+3=0

a = 5; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·5·3
Δ = -60
Delta is less than zero, so there is no solution for the equation

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