z2=25/9

Solution for z2=25/9 equation:

z2=25/9

We move all terms to the left:

z2-(25/9)=0

We add all the numbers together, and all the variables

z2-(+25/9)=0

We add all the numbers together, and all the variables

z^2-(+25/9)=0

We get rid of parentheses

z^2-25/9=0

We multiply all the terms by the denominator


z^2*9-25=0

Wy multiply elements

9z^2-25=0

a = 9; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·9·(-25)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*9}=\frac{-30}{18}
=-1+2/3
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*9}=\frac{30}{18}
=1+2/3
$