z2-12z+36=0

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Solution for z2-12z+36=0 equation: 



z2-12z+36=0

We add all the numbers together, and all the variables

z^2-12z+36=0

a = 1; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·1·36
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{12}{2}=6$

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