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z2+44z=0
We add all the numbers together, and all the variables
z^2+44z=0
a = 1; b = 44; c = 0;
Δ = b2-4ac
Δ = 442-4·1·0
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-44}{2*1}=\frac{-88}{2} =-44 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+44}{2*1}=\frac{0}{2} =0 $
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