z2(z-5)=9z+4

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Solution for z2(z-5)=9z+4 equation: 



z2(z-5)=9z+4

We move all terms to the left:

z2(z-5)-(9z+4)=0

We multiply parentheses

z^3-5z^2-(9z+4)=0

We get rid of parentheses

z^3-5z^2-9z-4=0

We do not support ezpression: z^3

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