z/3(2z-8)+10z=16

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Solution for z/3(2z-8)+10z=16 equation: 



z/3(2z-8)+10z=16

We move all terms to the left:

z/3(2z-8)+10z-(16)=0



Domain of the equation: 3(2z-8)!=0

z∈R



We add all the numbers together, and all the variables

10z+z/3(2z-8)-16=0

We multiply all the terms by the denominator


10z*3(2z-8)+z-16*3(2z-8)=0

We add all the numbers together, and all the variables

z+10z*3(2z-8)-16*3(2z-8)=0

Wy multiply elements

30z^2(2-48z(2+z=0

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