z/2+3=3-z/2

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Solution for z/2+3=3-z/2 equation: 



z/2+3=3-z/2

We move all terms to the left:

z/2+3-(3-z/2)=0

We add all the numbers together, and all the variables

z/2-(-z/2+3)+3=0

We get rid of parentheses

z/2+z/2-3+3=0

We multiply all the terms by the denominator


z+z-3*2+3*2=0

We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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