z-9/z-3z-20/7z

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Solution for z-9/z-3z-20/7z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

z-(3*z)-((20/7)*z)-(9/z) = 0

z-3*z+(-20/7)*z-9*z^-1 = 0

-34/7*z^1-9*z^-1 = 0

(-34/7*z^2-9*z^0)/(z^1) = 0 // * z^2

z^1*(-34/7*z^2-9*z^0) = 0

z^1

(-34/7)*z^2-9 = 0

(-34/7)*z^2-9 = 0

DELTA = 0^2-(-9*4*(-34/7))

DELTA = -1224/7

DELTA < 0

z in { } 

z belongs to the empty set

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