z-3(z+2)=-6-2z

Solution for z-3(z+2)=-6-2z equation:

Simplifying
z + -3(z + 2) = -6 + -2z

Reorder the terms:
z + -3(2 + z) = -6 + -2z
z + (2 * -3 + z * -3) = -6 + -2z
z + (-6 + -3z) = -6 + -2z

Reorder the terms:
-6 + z + -3z = -6 + -2z

Combine like terms: z + -3z = -2z
-6 + -2z = -6 + -2z

Add '6' to each side of the equation.
-6 + 6 + -2z = -6 + 6 + -2z

Combine like terms: -6 + 6 = 0
0 + -2z = -6 + 6 + -2z
-2z = -6 + 6 + -2z

Combine like terms: -6 + 6 = 0
-2z = 0 + -2z
-2z = -2z

Add '2z' to each side of the equation.
-2z + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
0 = -2z + 2z

Combine like terms: -2z + 2z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.