z+50=(z+14)+(z+1)

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Solution for z+50=(z+14)+(z+1) equation:



z+50=(z+14)+(z+1)
We move all terms to the left:
z+50-((z+14)+(z+1))=0
We calculate terms in parentheses: -((z+14)+(z+1)), so:
(z+14)+(z+1)
We get rid of parentheses
z+z+14+1
We add all the numbers together, and all the variables
2z+15
Back to the equation:
-(2z+15)
We get rid of parentheses
z-2z-15+50=0
We add all the numbers together, and all the variables
-1z+35=0
We move all terms containing z to the left, all other terms to the right
-z=-35
z=-35/-1
z=+35

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