z+50=(z+10)+4z

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Solution for z+50=(z+10)+4z equation: 



z+50=(z+10)+4z

We move all terms to the left:

z+50-((z+10)+4z)=0



We calculate terms in parentheses: -((z+10)+4z), so:

(z+10)+4z

We add all the numbers together, and all the variables

4z+(z+10)

We get rid of parentheses

4z+z+10

We add all the numbers together, and all the variables

5z+10

Back to the equation:

-(5z+10)



We get rid of parentheses

z-5z-10+50=0

We add all the numbers together, and all the variables

-4z+40=0

We move all terms containing z to the left, all other terms to the right

-4z=-40

z=-40/-4

z=+10

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