z+4(n+2)-n=0

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Solution for z+4(n+2)-n=0 equation:


Simplifying
z + 4(n + 2) + -1n = 0

Reorder the terms:
z + 4(2 + n) + -1n = 0
z + (2 * 4 + n * 4) + -1n = 0
z + (8 + 4n) + -1n = 0

Reorder the terms:
8 + 4n + -1n + z = 0

Combine like terms: 4n + -1n = 3n
8 + 3n + z = 0

Solving
8 + 3n + z = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 3n + -8 + z = 0 + -8

Reorder the terms:
8 + -8 + 3n + z = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 3n + z = 0 + -8
3n + z = 0 + -8

Combine like terms: 0 + -8 = -8
3n + z = -8

Add '-1z' to each side of the equation.
3n + z + -1z = -8 + -1z

Combine like terms: z + -1z = 0
3n + 0 = -8 + -1z
3n = -8 + -1z

Divide each side by '3'.
n = -2.666666667 + -0.3333333333z

Simplifying
n = -2.666666667 + -0.3333333333z

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