z+4(2z+3)=15z+4(2z+3)=15

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Solution for z+4(2z+3)=15z+4(2z+3)=15 equation: 



z+4(2z+3)=15z+4(2z+3)=15

We move all terms to the left:

z+4(2z+3)-(15z+4(2z+3))=0

We multiply parentheses

z+8z-(15z+4(2z+3))+12=0



We calculate terms in parentheses: -(15z+4(2z+3)), so:

15z+4(2z+3)

We multiply parentheses

15z+8z+12

We add all the numbers together, and all the variables

23z+12

Back to the equation:

-(23z+12)



We add all the numbers together, and all the variables

9z-(23z+12)+12=0

We get rid of parentheses

9z-23z-12+12=0

We add all the numbers together, and all the variables

-14z=0

z=0/-14

z=0

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