z+26=(z)2

Solution for z+26=(z)2 equation:

z+26=(z)2

We move all terms to the left:

z+26-((z)2)=0

determiningTheFunctionDomain
z-z2+26=0

We add all the numbers together, and all the variables

-1z^2+z+26=0

a = -1; b = 1; c = +26;
Δ = b2-4ac
Δ = 12-4·(-1)·26
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{105}}{2*-1}=\frac{-1-\sqrt{105}}{-2}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{105}}{2*-1}=\frac{-1+\sqrt{105}}{-2}
$