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z+1/2z=90
We move all terms to the left:
z+1/2z-(90)=0
Domain of the equation: 2z!=0We multiply all the terms by the denominator
z!=0/2
z!=0
z∈R
z*2z-90*2z+1=0
Wy multiply elements
2z^2-180z+1=0
a = 2; b = -180; c = +1;
Δ = b2-4ac
Δ = -1802-4·2·1
Δ = 32392
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{32392}=\sqrt{4*8098}=\sqrt{4}*\sqrt{8098}=2\sqrt{8098}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-180)-2\sqrt{8098}}{2*2}=\frac{180-2\sqrt{8098}}{4} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-180)+2\sqrt{8098}}{2*2}=\frac{180+2\sqrt{8098}}{4} $
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