z+(2-2)+5(z-2)=30

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Solution for z+(2-2)+5(z-2)=30 equation: 



z+(2-2)+5(z-2)=30

We move all terms to the left:

z+(2-2)+5(z-2)-(30)=0

determiningTheFunctionDomain
z+5(z-2)-30+(2-2)=0

We add all the numbers together, and all the variables

z+5(z-2)-30+0=0

We add all the numbers together, and all the variables

z+5(z-2)-30=0

We multiply parentheses

z+5z-10-30=0

We add all the numbers together, and all the variables

6z-40=0

We move all terms containing z to the left, all other terms to the right

6z=40

z=40/6

z=6+2/3

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