z+(2+i)z=3+5i

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Solution for z+(2+i)z=3+5i equation:


Simplifying
z + (2 + i) * z = 3 + 5i

Reorder the terms for easier multiplication:
z + z(2 + i) = 3 + 5i
z + (2 * z + i * z) = 3 + 5i

Reorder the terms:
z + (iz + 2z) = 3 + 5i
z + (iz + 2z) = 3 + 5i

Reorder the terms:
iz + z + 2z = 3 + 5i

Combine like terms: z + 2z = 3z
iz + 3z = 3 + 5i

Solving
iz + 3z = 3 + 5i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-5i' to each side of the equation.
iz + -5i + 3z = 3 + 5i + -5i

Reorder the terms:
-5i + iz + 3z = 3 + 5i + -5i

Combine like terms: 5i + -5i = 0
-5i + iz + 3z = 3 + 0
-5i + iz + 3z = 3

Add '-3z' to each side of the equation.
-5i + iz + 3z + -3z = 3 + -3z

Combine like terms: 3z + -3z = 0
-5i + iz + 0 = 3 + -3z
-5i + iz = 3 + -3z

Reorder the terms:
-3 + -5i + iz + 3z = 3 + -3z + -3 + 3z

Reorder the terms:
-3 + -5i + iz + 3z = 3 + -3 + -3z + 3z

Combine like terms: 3 + -3 = 0
-3 + -5i + iz + 3z = 0 + -3z + 3z
-3 + -5i + iz + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
-3 + -5i + iz + 3z = 0

The solution to this equation could not be determined.

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