z(3+2i)=(2-3i)

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Solution for z(3+2i)=(2-3i) equation:


Simplifying
z(3 + 2i) = (2 + -3i)
(3 * z + 2i * z) = (2 + -3i)

Reorder the terms:
(2iz + 3z) = (2 + -3i)
(2iz + 3z) = (2 + -3i)

Remove parenthesis around (2 + -3i)
2iz + 3z = 2 + -3i

Solving
2iz + 3z = 2 + -3i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3i' to each side of the equation.
2iz + 3i + 3z = 2 + -3i + 3i

Reorder the terms:
3i + 2iz + 3z = 2 + -3i + 3i

Combine like terms: -3i + 3i = 0
3i + 2iz + 3z = 2 + 0
3i + 2iz + 3z = 2

Add '-3z' to each side of the equation.
3i + 2iz + 3z + -3z = 2 + -3z

Combine like terms: 3z + -3z = 0
3i + 2iz + 0 = 2 + -3z
3i + 2iz = 2 + -3z

Reorder the terms:
-2 + 3i + 2iz + 3z = 2 + -3z + -2 + 3z

Reorder the terms:
-2 + 3i + 2iz + 3z = 2 + -2 + -3z + 3z

Combine like terms: 2 + -2 = 0
-2 + 3i + 2iz + 3z = 0 + -3z + 3z
-2 + 3i + 2iz + 3z = -3z + 3z

Combine like terms: -3z + 3z = 0
-2 + 3i + 2iz + 3z = 0

The solution to this equation could not be determined.

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