z(2+i)=1-4i

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Solution for z(2+i)=1-4i equation:


Simplifying
z(2 + i) = 1 + -4i
(2 * z + i * z) = 1 + -4i

Reorder the terms:
(iz + 2z) = 1 + -4i
(iz + 2z) = 1 + -4i

Solving
iz + 2z = 1 + -4i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '4i' to each side of the equation.
iz + 4i + 2z = 1 + -4i + 4i

Reorder the terms:
4i + iz + 2z = 1 + -4i + 4i

Combine like terms: -4i + 4i = 0
4i + iz + 2z = 1 + 0
4i + iz + 2z = 1

Add '-2z' to each side of the equation.
4i + iz + 2z + -2z = 1 + -2z

Combine like terms: 2z + -2z = 0
4i + iz + 0 = 1 + -2z
4i + iz = 1 + -2z

Reorder the terms:
-1 + 4i + iz + 2z = 1 + -2z + -1 + 2z

Reorder the terms:
-1 + 4i + iz + 2z = 1 + -1 + -2z + 2z

Combine like terms: 1 + -1 = 0
-1 + 4i + iz + 2z = 0 + -2z + 2z
-1 + 4i + iz + 2z = -2z + 2z

Combine like terms: -2z + 2z = 0
-1 + 4i + iz + 2z = 0

The solution to this equation could not be determined.

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