z(1+i)=6-2i

Solution for z(1+i)=6-2i equation:

Simplifying
z(1 + i) = 6 + -2i
(1 * z + i * z) = 6 + -2i

Reorder the terms:
(iz + 1z) = 6 + -2i
(iz + 1z) = 6 + -2i

Solving
iz + 1z = 6 + -2i

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '2i' to each side of the equation.
iz + 2i + 1z = 6 + -2i + 2i

Reorder the terms:
2i + iz + 1z = 6 + -2i + 2i

Combine like terms: -2i + 2i = 0
2i + iz + 1z = 6 + 0
2i + iz + 1z = 6

Add '-1z' to each side of the equation.
2i + iz + 1z + -1z = 6 + -1z

Combine like terms: 1z + -1z = 0
2i + iz + 0 = 6 + -1z
2i + iz = 6 + -1z

Reorder the terms:
-6 + 2i + iz + z = 6 + -1z + -6 + z

Reorder the terms:
-6 + 2i + iz + z = 6 + -6 + -1z + z

Combine like terms: 6 + -6 = 0
-6 + 2i + iz + z = 0 + -1z + z
-6 + 2i + iz + z = -1z + z

Combine like terms: -1z + z = 0
-6 + 2i + iz + z = 0

The solution to this equation could not be determined.