y=6(3/2)+19

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Solution for y=6(3/2)+19 equation: 



y=6(3/2)+19

We move all terms to the left:

y-(6(3/2)+19)=0

We add all the numbers together, and all the variables

y-(6(+3/2)+19)=0

We multiply all the terms by the denominator


y*2)+19)-(6(+3=0

Wy multiply elements

2y^2+3=0

a = 2; b = 0; c = +3;
Δ = b2-4ac
Δ = 02-4·2·3
Δ = -24
Delta is less than zero, so there is no solution for the equation

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