y=3x+4/x-3

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Solution for y=3x+4/x-3 equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

y = 3*x+4/x-3 // - 3*x+4/x-3

y-(3*x)-(4/x)+3 = 0

y-3*x-4*x^-1+3 = 0

3*x^0-3*x^1-4*x^-1 = 0

(3*x^1-3*x^2-4*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^1-3*x^2-4*x^0) = 0

x^1

3*x-3*x^2-4 = 0

3*x-3*x^2-4 = 0

DELTA = 3^2-(-4*(-3)*4)

DELTA = -39

DELTA < 0

x in { } 

x belongs to the empty set

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