y=3X2-20

Solution for y=3X2-20 equation:

y=3y^2-20

We move all terms to the left:

y-(3y^2-20)=0

We get rid of parentheses

-3y^2+y+20=0

a = -3; b = 1; c = +20;
Δ = b2-4ac
Δ = 12-4·(-3)·20
Δ = 241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{241}}{2*-3}=\frac{-1-\sqrt{241}}{-6}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{241}}{2*-3}=\frac{-1+\sqrt{241}}{-6}
$