y=3/2x+19/2

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Solution for y=3/2x+19/2 equation: 


x in (-oo:+oo)

y = (3/2)*x+19/2 // - (3/2)*x+19/2

y-((3/2)*x)-(19/2) = 0

(-3/2)*x+y-19/2 = 0

y-3/2*x-19/2 = 0 // - y-19/2

-3/2*x = -(y-19/2) // : -3/2

x = (-(y-19/2))/(-3/2)

x = -2/3*(19/2-y)

x = -2/3*(19/2-y)

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