y=225+(25y/(500))

Solution for y=225+(25y/(500)) equation:

y=225+(25y/(500))

We move all terms to the left:

y-(225+(25y/(500)))=0

We add all the numbers together, and all the variables

y-(225+(+25y/500))=0

We multiply all the terms by the denominator


y*500))-(225+(+25y=0

We add all the numbers together, and all the variables

25y+y*500))-(225+(=0

Wy multiply elements

500y^2+25y=0

a = 500; b = 25; c = 0;
Δ = b2-4ac
Δ = 252-4·500·0
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{625}=25$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-25}{2*500}=\frac{-50}{1000}
=-1/20
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+25}{2*500}=\frac{0}{1000}
=0
$