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y=2(3y+5)=3(5y+(1/3))
We move all terms to the left:
y-(2(3y+5))=0
We calculate terms in parentheses: -(2(3y+5)), so:We get rid of parentheses
2(3y+5)
We multiply parentheses
6y+10
Back to the equation:
-(6y+10)
y-6y-10=0
We add all the numbers together, and all the variables
-5y-10=0
We move all terms containing y to the left, all other terms to the right
-5y=10
y=10/-5
y=-2
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