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y=2(23/12)-5
We move all terms to the left:
y-(2(23/12)-5)=0
We add all the numbers together, and all the variables
y-(2(+23/12)-5)=0
We multiply all the terms by the denominator
y*12)-5)-(2(+23=0
Wy multiply elements
12y^2+23=0
a = 12; b = 0; c = +23;
Δ = b2-4ac
Δ = 02-4·12·23
Δ = -1104
Delta is less than zero, so there is no solution for the equation
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