y=12-(2y-3)

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Solution for y=12-(2y-3) equation: 



y=12-(2y-3)

We move all terms to the left:

y-(12-(2y-3))=0



We calculate terms in parentheses: -(12-(2y-3)), so:

12-(2y-3)

determiningTheFunctionDomain
-(2y-3)+12

We get rid of parentheses

-2y+3+12

We add all the numbers together, and all the variables

-2y+15

Back to the equation:

-(-2y+15)



We get rid of parentheses

y+2y-15=0

We add all the numbers together, and all the variables

3y-15=0

We move all terms containing y to the left, all other terms to the right

3y=15

y=15/3

y=5

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