y=(4y-8)(79+y)

Solution for y=(4y-8)(79+y) equation:

y=(4y-8)(79+y)

We move all terms to the left:

y-((4y-8)(79+y))=0

We add all the numbers together, and all the variables

y-((4y-8)(y+79))=0

We multiply parentheses ..

-((+4y^2+316y-8y-632))+y=0


We calculate terms in parentheses: -((+4y^2+316y-8y-632)), so:

(+4y^2+316y-8y-632)

We get rid of parentheses

4y^2+316y-8y-632

We add all the numbers together, and all the variables

4y^2+308y-632

Back to the equation:

-(4y^2+308y-632)


We add all the numbers together, and all the variables

y-(4y^2+308y-632)=0

We get rid of parentheses

-4y^2+y-308y+632=0

We add all the numbers together, and all the variables

-4y^2-307y+632=0

a = -4; b = -307; c = +632;
Δ = b2-4ac
Δ = -3072-4·(-4)·632
Δ = 104361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-307)-\sqrt{104361}}{2*-4}=\frac{307-\sqrt{104361}}{-8}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-307)+\sqrt{104361}}{2*-4}=\frac{307+\sqrt{104361}}{-8}
$