y=(3y-40)+(y+10)

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Solution for y=(3y-40)+(y+10) equation: 



y=(3y-40)+(y+10)

We move all terms to the left:

y-((3y-40)+(y+10))=0



We calculate terms in parentheses: -((3y-40)+(y+10)), so:

(3y-40)+(y+10)

We get rid of parentheses

3y+y-40+10

We add all the numbers together, and all the variables

4y-30

Back to the equation:

-(4y-30)



We get rid of parentheses

y-4y+30=0

We add all the numbers together, and all the variables

-3y+30=0

We move all terms containing y to the left, all other terms to the right

-3y=-30

y=-30/-3

y=+10

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