y=((x+1)(x+1))-4

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Solution for y=((x+1)(x+1))-4 equation: 


Simplifying
y = ((x + 1)(x + 1)) + -4

Reorder the terms:
y = ((1 + x)(x + 1)) + -4

Reorder the terms:
y = ((1 + x)(1 + x)) + -4

Multiply (1 + x) * (1 + x)
y = ((1(1 + x) + x(1 + x))) + -4
y = (((1 * 1 + x * 1) + x(1 + x))) + -4
y = (((1 + 1x) + x(1 + x))) + -4
y = ((1 + 1x + (1 * x + x * x))) + -4
y = ((1 + 1x + (1x + x2))) + -4

Combine like terms: 1x + 1x = 2x
y = ((1 + 2x + x2)) + -4
y = (1 + 2x + x2) + -4

Remove parenthesis around (1 + 2x + x2)
y = 1 + 2x + x2 + -4

Reorder the terms:
y = 1 + -4 + 2x + x2

Combine like terms: 1 + -4 = -3
y = -3 + 2x + x2

Solving
y = -3 + 2x + x2

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Simplifying
y = -3 + 2x + x2

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