y2=9/12

Solution for y2=9/12 equation:

y2=9/12

We move all terms to the left:

y2-(9/12)=0

We add all the numbers together, and all the variables

y2-(+9/12)=0

We add all the numbers together, and all the variables

y^2-(+9/12)=0

We get rid of parentheses

y^2-9/12=0

We multiply all the terms by the denominator


y^2*12-9=0

Wy multiply elements

12y^2-9=0

a = 12; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·12·(-9)
Δ = 432
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{432}=\sqrt{144*3}=\sqrt{144}*\sqrt{3}=12\sqrt{3}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{3}}{2*12}=\frac{0-12\sqrt{3}}{24}
=-\frac{12\sqrt{3}}{24}
=-\frac{\sqrt{3}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{3}}{2*12}=\frac{0+12\sqrt{3}}{24}
=\frac{12\sqrt{3}}{24}
=\frac{\sqrt{3}}{2}
$