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y2=250.y=
We move all terms to the left:
y2-(250.y)=0
We add all the numbers together, and all the variables
y2-(+250.y)=0
We add all the numbers together, and all the variables
y^2-(+250.y)=0
We get rid of parentheses
y^2-250.y=0
We add all the numbers together, and all the variables
y^2-250y=0
a = 1; b = -250; c = 0;
Δ = b2-4ac
Δ = -2502-4·1·0
Δ = 62500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{62500}=250$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-250}{2*1}=\frac{0}{2} =0 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+250}{2*1}=\frac{500}{2} =250 $
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