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y2=0.82
We move all terms to the left:
y2-(0.82)=0
We add all the numbers together, and all the variables
y^2-0.82=0
a = 1; b = 0; c = -0.82;
Δ = b2-4ac
Δ = 02-4·1·(-0.82)
Δ = 3.28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{3.28}}{2*1}=\frac{0-\sqrt{3.28}}{2} =-\frac{\sqrt{}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{3.28}}{2*1}=\frac{0+\sqrt{3.28}}{2} =\frac{\sqrt{}}{2} $
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