y2-2y=(y-2)*(y+3)

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Solution for y2-2y=(y-2)*(y+3) equation: 



y2-2y=(y-2)(y+3)

We move all terms to the left:

y2-2y-((y-2)(y+3))=0

We add all the numbers together, and all the variables

y^2-2y-((y-2)(y+3))=0

We multiply parentheses ..

y^2-((+y^2+3y-2y-6))-2y=0



We calculate terms in parentheses: -((+y^2+3y-2y-6)), so:

(+y^2+3y-2y-6)

We get rid of parentheses

y^2+3y-2y-6

We add all the numbers together, and all the variables

y^2+y-6

Back to the equation:

-(y^2+y-6)



We add all the numbers together, and all the variables

y^2-2y-(y^2+y-6)=0

We get rid of parentheses

y^2-y^2-2y-y+6=0

We add all the numbers together, and all the variables

-3y+6=0

We move all terms containing y to the left, all other terms to the right

-3y=-6

y=-6/-3

y=+2

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