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y2-2.4y-1.44=0
We add all the numbers together, and all the variables
y^2-2.4y-1.44=0
a = 1; b = -2.4; c = -1.44;
Δ = b2-4ac
Δ = -2.42-4·1·(-1.44)
Δ = 11.52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.4)-\sqrt{11.52}}{2*1}=\frac{2.4-\sqrt{11.52}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.4)+\sqrt{11.52}}{2*1}=\frac{2.4+\sqrt{11.52}}{2} $
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