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y2-18y=63
We move all terms to the left:
y2-18y-(63)=0
We add all the numbers together, and all the variables
y^2-18y-63=0
a = 1; b = -18; c = -63;
Δ = b2-4ac
Δ = -182-4·1·(-63)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-24}{2*1}=\frac{-6}{2} =-3 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+24}{2*1}=\frac{42}{2} =21 $
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