y2+7=(y-1)2+3y

Solution for y2+7=(y-1)2+3y equation:

y2+7=(y-1)2+3y

We move all terms to the left:

y2+7-((y-1)2+3y)=0

We add all the numbers together, and all the variables

y^2-((y-1)2+3y)+7=0


We calculate terms in parentheses: -((y-1)2+3y), so:

(y-1)2+3y

We add all the numbers together, and all the variables

3y+(y-1)2

We multiply parentheses

3y+2y-2

We add all the numbers together, and all the variables

5y-2

Back to the equation:

-(5y-2)


We get rid of parentheses

y^2-5y+2+7=0

We add all the numbers together, and all the variables

y^2-5y+9=0

a = 1; b = -5; c = +9;
Δ = b2-4ac
Δ = -52-4·1·9
Δ = -11
Delta is less than zero, so there is no solution for the equation