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y2+4.891y-5.8940=0
We add all the numbers together, and all the variables
y^2+4.891y-5.894=0
a = 1; b = 4.891; c = -5.894;
Δ = b2-4ac
Δ = 4.8912-4·1·(-5.894)
Δ = 47.497881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.891)-\sqrt{47.497881}}{2*1}=\frac{-4.891-\sqrt{47.497881}}{2} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.891)+\sqrt{47.497881}}{2*1}=\frac{-4.891+\sqrt{47.497881}}{2} $
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