y/8y+4(4y-3)=4(6y+4)-4

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Solution for y/8y+4(4y-3)=4(6y+4)-4 equation: 



y/8y+4(4y-3)=4(6y+4)-4

We move all terms to the left:

y/8y+4(4y-3)-(4(6y+4)-4)=0



Domain of the equation: 8y!=0

y!=0/8

y!=0

y∈R



We multiply parentheses

y/8y+16y-(4(6y+4)-4)-12=0

We multiply all the terms by the denominator


y+16y*8y-((4(6y+4)-4))*8y-12*8y=0

Wy multiply elements

128y^2+y-((4(6y+4)-4))*8y-96y=0

We add all the numbers together, and all the variables

128y^2-95y-((4(6y+4)-4))*8y=0

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