y/5(2y-1)=15

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Solution for y/5(2y-1)=15 equation: 



y/5(2y-1)=15

We move all terms to the left:

y/5(2y-1)-(15)=0



Domain of the equation: 5(2y-1)!=0

y∈R



We multiply all the terms by the denominator


y-15*5(2y-1)=0

Wy multiply elements

y-75y(2=0

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