y/4=(y+1)/6

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Solution for y/4=(y+1)/6 equation: 



y/4=(y+1)/6

We move all terms to the left:

y/4-((y+1)/6)=0

We calculate fractions


6y^2/()+(-((y+1)*4)/()=0



We calculate terms in parentheses: +(-((y+1)*4)/(), so:

-((y+1)*4)/(

We multiply all the terms by the denominator


-((y+1)*4)



We calculate terms in parentheses: -((y+1)*4), so:

(y+1)*4

We multiply parentheses

4y+4

Back to the equation:

-(4y+4)



We get rid of parentheses

-4y-4

Back to the equation:

+(-4y-4)



We get rid of parentheses

6y^2/()-4y-4=0

We multiply all the terms by the denominator


6y^2-4y*()-4*()=0

We add all the numbers together, and all the variables

6y^2-4y*()=0

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