y/(y-2)=(y-3)/y

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Solution for y/(y-2)=(y-3)/y equation: 


D( y )

y = 0

y-2 = 0

y = 0

y = 0

y-2 = 0

y-2 = 0

y-2 = 0 // + 2

y = 2

y in (-oo:0) U (0:2) U (2:+oo)

y/(y-2) = (y-3)/y // - (y-3)/y

y/(y-2)-((y-3)/y) = 0

y/(y-2)+(-1*(y-3))/y = 0

(y^2)/(y*(y-2))+(-1*(y-3)*(y-2))/(y*(y-2)) = 0

y^2-1*(y-3)*(y-2) = 0

5*y-6 = 0

(5*y-6)/(y*(y-2)) = 0

(5*y-6)/(y*(y-2)) = 0 // * y*(y-2)

5*y-6 = 0

5*y-6 = 0 // + 6

5*y = 6 // : 5

y = 6/5

y = 6/5

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