y-8(y-8)=(-9y+2)-3

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Solution for y-8(y-8)=(-9y+2)-3 equation: 



y-8(y-8)=(-9y+2)-3

We move all terms to the left:

y-8(y-8)-((-9y+2)-3)=0

We multiply parentheses

y-8y-((-9y+2)-3)+64=0



We calculate terms in parentheses: -((-9y+2)-3), so:

(-9y+2)-3

We get rid of parentheses

-9y+2-3

We add all the numbers together, and all the variables

-9y-1

Back to the equation:

-(-9y-1)



We add all the numbers together, and all the variables

-7y-(-9y-1)+64=0

We get rid of parentheses

-7y+9y+1+64=0

We add all the numbers together, and all the variables

2y+65=0

We move all terms containing y to the left, all other terms to the right

2y=-65

y=-65/2

y=-32+1/2

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