y-5=3-9(y+12)

Solution for y-5=3-9(y+12) equation:

y-5=3-9(y+12)

We move all terms to the left:

y-5-(3-9(y+12))=0


We calculate terms in parentheses: -(3-9(y+12)), so:

3-9(y+12)

determiningTheFunctionDomain
-9(y+12)+3

We multiply parentheses

-9y-108+3

We add all the numbers together, and all the variables

-9y-105

Back to the equation:

-(-9y-105)


We get rid of parentheses

y+9y+105-5=0

We add all the numbers together, and all the variables

10y+100=0

We move all terms containing y to the left, all other terms to the right

10y=-100

y=-100/10

y=-10