y-5=3-9(1y+2)

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Solution for y-5=3-9(1y+2) equation: 



y-5=3-9(1y+2)

We move all terms to the left:

y-5-(3-9(1y+2))=0

We add all the numbers together, and all the variables

y-(3-9(y+2))-5=0



We calculate terms in parentheses: -(3-9(y+2)), so:

3-9(y+2)

determiningTheFunctionDomain
-9(y+2)+3

We multiply parentheses

-9y-18+3

We add all the numbers together, and all the variables

-9y-15

Back to the equation:

-(-9y-15)



We get rid of parentheses

y+9y+15-5=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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