y-4+3y=2(3y-8)

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Solution for y-4+3y=2(3y-8) equation: 



y-4+3y=2(3y-8)

We move all terms to the left:

y-4+3y-(2(3y-8))=0

We add all the numbers together, and all the variables

4y-(2(3y-8))-4=0



We calculate terms in parentheses: -(2(3y-8)), so:

2(3y-8)

We multiply parentheses

6y-16

Back to the equation:

-(6y-16)



We get rid of parentheses

4y-6y+16-4=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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