y-4(y+1)/y+2-4/y+2

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Solution for y-4(y+1)/y+2-4/y+2 equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-((4*(y+1))/y)-(4/y)+2+2 = 0

y-4*y^-1*(y+1)-4*y^-1+2+2 = 0

y-4*y^-1*(y+1)-4/y+2+2 = 0

(-4*y^-1*y*(y+1))/y+(y^2)/y-4/y+(2*y)/y+(2*y)/y = 0

y^2-4*y^-1*y*(y+1)+2*y+2*y-4 = 0

y^2-4*y+2*y+2*y-4-4 = 0

y^2-4*y+2*y+2*y-8 = 0

y^2-2*y+2*y-8 = 0

y^2-8 = 0

(y^2-8)/y = 0

(y^2-8)/y = 0 // * y

y^2-8 = 0

1*y^2 = 8 // : 1

y^2 = 8

y^2 = 8 // ^ 1/2

abs(y) = 2*2^(1/2)

y = 2*2^(1/2) or y = -(2*2^(1/2))

y in { 2*2^(1/2), -(2*2^(1/2)) }

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